Web7. Find t21, if S41 = 4510 in an A.P. 8. In an A.P. t10=57 and t15=87 then find t21. 9. If Rs.3900 will have to repay In 12 monthly instalments such that each instalment being more than the preceding one by Rs.10, then find the amount of the first and last instalment. 10. Web9) The solution of the equation x-y=10 and x+y=70 is -----., A) (40,30), , B) (30,40), , C) (10,60), , D) (50,20), , 10) Find the value of Dx for the equation 4š„ + 3 š¦ = 19 and 4 š„ ā, 3 š¦ = ā11, A) 24, , B) 0, , C) ā24, , D) 108, , Q. 1 B) Each of 1 mark, 1) State with reason whether the equation 3š„ 2 ā¦
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WebAug 8, 2024 Ā· T1+t5+t10+t15-----=225 find the sum of first 24 terms of AP Get the answers you need, now! mini3885 mini3885 08.08.2024 Math Secondary School answered T1+t5+t10+t15-----=225 find the sum of first 24 terms of AP See answers Advertisement Advertisement singhaksh65 singhaksh65 Answer-S24th term= 24/2(2a+(24-1)d) WebFeb 20, 2024 Ā· A merchant borrows Rs.1000 and agrees to repay its interest Rs.140, with principal in 12 monthly instalments. Each instalment being less, than the preceding one by ā¦ imaginext flash toys
Find S10 if a = 6 and d = 3 . Maths Questions - Toppr
WebAug 3, 2024 Ā· (ii) Understanding to find tn term of an A.P. (U) to find an A.M. between two terms. to find sum of n terms of an A.P. (iii) Application (A) to find a, d of an A.P. when two terms are given. to find n A.M.'s between two terms. to find number of means when two extreme term are given. (iv) Higher Ability to find number of terms when sum of an A.P ... WebLet the number of terms in the A.P. be n. Then, t n = 101 Since t n = a + (n ā 1)d, 101 = 1 + (n ā 1) (2) ā“ 101 = 1 + 2n ā 2 ā“ 101 = 2n ā 1 ā“ 102 = 2n ā“ n = 102 2 = 51 Now, S n = n t t n n 2 ( t 1 + t n) ā“ S 51 = 51 2 ( 1 + 101) = 51 2 ( 102) = 51 Ć 51 = 2601 ā“ The sum of odd natural numbers from 1 to 101 is 2601. WebFor an A.P., let a be the first term and d be the common difference. S 55 = 3300 .....[Given] We know that, Since S n = `"n"/2`[2a + (n ā 1)d] ā“ S 55 = `55/2`[2a + (55 ā 1) d] ā“ 3300 = `55/2`[2a + 54d] ā“ 3300 = `55/2` Ć 2[a + 27d] ā“ 3300 = 55[a + 27d] ā“ a + 27d = `3300/55` ā“ a + 27d = 60 .....(i) Now, t n = a + (n ā 1)d imaginext fisher price batman